Within A Period Of One Second, 5 X 1023 Nitrogen

This text discusses various online tools that can be used for calculations and conversions involving scientific notation, E-notation, engineering notation, and real numbers. It also mentions a specific example of converting 5,000,000,000 to scientific notation and using the Boltzmann constant (kB or k) in a calculation. The text also highlights the availability of free math problem solvers and calculators for subjects such as Pre-Algebra, Algebra, Trigonometry, Calculus, Geometry, Statistics, and Chemistry, with step-by-step explanations. The problem-solving methods demonstrated in class are also encouraged to be used when solving problems.

To calculate the pressure exerted on the wall, we can use the formula for pressure, which is given by:

[ P = \frac{F}{A} ]

Where: P = pressure F = force A = area

We can find the force exerted by the nitrogen molecules using the following information: Number of molecules (n) = 5 x 10^23 molecules Speed of molecules (v) = 300 m/s Mass of one nitrogen molecule (m) = 4.68 x 10^-26 kg

The force exerted by the molecules can be calculated using the formula:

[ F = \Delta p / \Delta t ]

Where: Δp = change in momentum Δt = change in time

The change in momentum can be calculated as: [ \Delta p = 2mv ]

Where: m = mass of one nitrogen molecule v = speed of the molecules

Substituting the given values: [ \Delta p = 2 \times (4.68 \times 10^{-26} , \text{kg}) \times (300 , \text{m/s}) ] [ \Delta p = 2 \times 4.68 \times 300 \times 10^{-26} , \text{kg m/s} ] [ \Delta p = 2 \times 4.68 \times 300 \times 10^{-26} , \text{N s} ]

Now, we can calculate the force using the change in momentum and the given time period.

Let me calculate that.

M/23/5'10" [300lbs > 208lbs = 92lbs] (16 months) The road so far ...In a period of 1.00 s, 5.00 times 10^{23} nitrogen molecules ...

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