The Concetration And Osmolarity Of 180 Gr Of Glucose And

Osmolality is a measure of concentration in a solution, specifically the number of solutes per kilogram or liter of water in the solution. It can be calculated by dividing the osmolarity by the amount of plasma water. Osmolarity is determined by multiplying the molarity by the number of osmoles each solute produces. This means that osmolarity depends on the number of impermeant molecules present, rather than their identity. For example, a 1M solution of nonionizing glucose has the same osmolarity as a 1M solution of NaCl. The molar mass of a solute, such as NaCl or glucose, can also be used to calculate the osmotic pressure of a solution.

To calculate the concentration and osmolarity of the given solutions, we can use the following formulas:

Concentration (in g/L) = (mass of solute in g) / (volume of solution in L)

Osmolarity (in osmoles/L) = (molarity of the solution) * (number of particles produced by the solute)

Let's begin by calculating the concentration and osmolarity of glucose and sodium chloride separately.

For the 180g of glucose per liter of solution:

Concentration of glucose = 180g / 1L = 180g/L

Osmolarity of glucose: Glucose (C6H12O6) is a non-ionizing solute. Therefore, the osmolarity will be the same as the molarity.

Molar mass of glucose (C6H12O6) = 180.16 g/mol The molarity of the solution is equal to the concentration in this case (180g/L). Therefore, the osmolarity will also be 180g/L.

For the 58.5g of sodium chloride per liter of solution:

Concentration of sodium chloride = 58.5g / 1L = 58.5g/L

Osmolarity of sodium chloride: Sodium chloride (NaCl) dissociates into Na+ and Cl- ions, so it produces 2 particles in solution.

Molar mass of NaCl = 58.44 g/mol The molarity of the solution will be (58.5g / 58.44g/mol) = 1 mol/L. Thus, the osmolarity will be 1 mol/L * 2 = 2 osmoles/L.

Therefore, for the given solutions, we have: Concentration of glucose = 180g/L Osmolarity of glucose = 180g/L Concentration of sodium chloride = 58.5g/L Osmolarity of sodium chloride = 2 osmoles/L

Solved Assuming question 1 is correct, I have 2 | Chegg.comSolved Critical Thinking Assignment 1: Osmolarity and | Chegg.com

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