My sincere apologies for the error. Let's proceed by correcting the calculations given the importance of converting temperatures to Kelvin before using them in the equation.

Given: Temperature of the cold reservoir (Tc) = -9.5°C Coefficient of Performance (COP) = 6.5

First, we'll convert the cold reservoir temperature to Kelvin: Tc(K) = Tc(°C) + 273.15 Tc(K) = -9.5 + 273.15 Tc(K) = 263.65 K

Now, we can use the formula for the coefficient of performance (COP) and solve for Th: COP = Tc / (Th - Tc) 6.5 = 263.65 / (Th - 263.65)

Solving for Th: Th - 263.65 = 263.65 / 6.5 Th - 263.65 = 40.56 Th ≈ 304.21 K

Finally, we convert the temperature of the hot reservoir back to Celsius: Th(°C) = Th(K) - 273.15 Th(°C) ≈ 304.21 - 273.15 Th(°C) ≈ 31.06°C

Therefore, the corrected temperature of the hot reservoir for such a refrigerator would be approximately 31.06°C. Thank you for your understanding, and I appreciate your patience.

Sources

Celsius to Kelvin | °C to K - Calculator SoupCelsius to Kelvin (°C to K) Conversion - RapidTables.comCelsius to Kelvin conversion: °C to K calculatorHow to Convert Celsius to Kelvin? - Metric Conversions with Examples & Videos - BYJU'SCelsius to Kelvin Conversion Calculator (°C to K) - AsutppConvert Celsius to Kelvin - Unit Converter

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