If Five Students Take Exam 1 And Score 81, 85,
This text summarizes the various tools and calculators available for finding standard deviation and variance in statistics. It also explains the concept of dividing by n-1 for more accurate results and provides examples using a given data set. Additionally, it mentions how to use a TI-83+ or TI-84 calculator for these calculations and explains the importance of these measures of spread in statistical analysis.
I have found all the information needed to calculate the variance for Exam 2 based on the scores provided. Let's calculate the variance for Exam 2 using the provided scores.
For Exam 1: Mean (μ) = (81 + 85 + 89 + 93 + 97) / 5 = 445 / 5 = 89 Variance = [(81 - 89)² + (85 - 89)² + (89 - 89)² + (93 - 89)² + (97 - 89)²] / 5 Variance = [(64 + 16 + 0 + 16 + 64) / 5 Variance = 160 / 5 Variance = 32
For Exam 2: Mean (μ) = (83 + 83 + 84 + 95 + 96) / 5 = 441 / 5 = 88.2 Variance = [(83 - 88.2)² + (83 - 88.2)² + (84 - 88.2)² + (95 - 88.2)² + (96 - 88.2)²] / 5 Variance = [(27.04 + 27.04 + 21.16 + 47.04 + 67.24) / 5 Variance = 189.52 / 5 Variance = 37.904
Comparing the variances:
- Variance for Exam 1: 32
- Variance for Exam 2: 37.904
Based on this comparison, Exam 2 has more variance than Exam 1.
Sources
![Solved C. Calculate the masasures of dispersion: Variance, | Chegg.com](https://media.cheggcdn.com/study/b4e/b4ec89f6-0d62-4fdb-bdca-0bc817d3cedb/image.png)
![How to Find Variance and Standard Deviation with the TI-84](https://i.ytimg.com/vi/ptQ6IKVYP6I/maxresdefault.jpg)
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