A Negative Charge \( 200 \mu \mathrm{c} \) And A

The Coulomb constant, denoted as k, is equal to 8.9875 x 109 N·m2/C2 and is used in the equation to calculate the electric field E for a given charge. In addition, the text also mentions the permittivity of free space, denoted as eo, which is equal to 8.8542 x 10-12 C2 / N·m2. This is followed by information about electric charge and the force between two charged particles, which is also influenced by the Coulomb constant. It is important to note that this constant has a similar role as the gravitational constant does in determining the force of attraction between two masses. The video answer also introduces the concept of typical charges being in the µC range and reminds to use Coulombs when solving calculations. Lastly, the text reminds readers of Coulomb's Law in vector form and mentions the influence of dielectric material on the constant.

The force between two charges can be calculated using Coulomb's law, which states that the force ((F)) between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between their centers. Coulomb's law is expressed as:

[ F = k \frac{ |q_1 \cdot q_2| }{ r^2 } ]

Where: ( k = 8.9875 \times 10^9 N m^2 / C^2 ) is the Coulomb constant. ( q_1 = -200 \mu C = -200 \times 10^{-6} C ) is the first charge. ( q_2 = 800 \mu C = 800 \times 10^{-6} C ) is the second charge. ( r = 30 cm = 0.3 m ) is the distance between the charges.

Substituting these values into the formula:

[ F = 8.9875 \times 10^9 \frac{ |(-200 \times 10^{-6} C) \cdot (800 \times 10^{-6} C)| }{ (0.3 m)^2 } ]

Let's calculate this.

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