(b) Trace The Output For The Following Fragment. Assume String
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Given the operation described, it appears that you want to trace the output after the provided code is executed for the string T = "C++ ProGraMminG". Let's work through this step by step.
- Initialize string T = "C++ ProGraMminG".
- Start the loop with i = 0. Check if T[i] != '\0'.
- The first character is 'C'. Since it's not 'A' or 'E', and is uppercase, it's transformed to lowercase. So T = "c".
- Increment i by 2. Now i = 2.
- The character at position 2 is '+'. It's not 'A', 'E', or an uppercase character. Therefore, it's transformed to '@'. T = "c@".
- Increment i by 2. Now i = 4.
- The character at position 4 is 'P'. It's not 'A', 'E', or an uppercase character. Therefore, it's transformed to '@'. T = "c@ @".
- Increment i by 2. Now i = 6.
- The character at position 6 is 'a'. It's neither 'A' nor an uppercase character. Therefore, it's transformed to '@'. T = "c@ @@".
- Increment i by 2. Now i = 8.
- The character at position 8 is 'm'. It's neither 'A' nor an uppercase character. Therefore, it's transformed to '@'. T = "c@ @@@".
- Increment i by 2. Now i = 10.
- The character at position 10 is 'n'. It's neither 'A' nor an uppercase character. Therefore, it's transformed to '@'. T = "c@ @@@@".
- Increment i by 2. Now i = 12.
- Since T[12] is '\0', the loop terminates.
So, after the above operations, the final value of string T will be "c@ @@@@".
I hope this helps! If you have further questions or need additional assistance, please feel free to ask.
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